x^2+(0.0020)x-9100000=0

Solution for x^2+(0.0020)x-9100000=0 equation:

x^2+(0.0020)x-9100000=0

We add all the numbers together, and all the variables

x^2+(0.002)x-9100000=0

We multiply parentheses

x^2+0.002x-9100000=0

a = 1; b = 0.002; c = -9100000;
Δ = b2-4ac
Δ = 0.0022-4·1·(-9100000)
Δ = 36400000.000004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.002)-\sqrt{36400000.000004}}{2*1}=\frac{-0.002-\sqrt{36400000.000004}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.002)+\sqrt{36400000.000004}}{2*1}=\frac{-0.002+\sqrt{36400000.000004}}{2}
$